A car stopped after travelling distance 8m due to applying brakes at the speed of 40 m/s. Find acceleration and retordation of car in that period. (`v^(2)-u^(2)=2as`)

Explanation

Here u = 40 m/s, v = 0 (vehical stopped), s = 8m, a = ?
`v^(2)-u^(2)=2as`
`0-40^(2)=2xxaxx8`
`a=(-(40)(40))/(2xx8)=-100m//s^(2)`
Acceleration = `100m//s^(2)` with retordation on (- sign).