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The distance travelled by a pparticle in...

The distance travelled by a pparticle in time 't' is given by `S=(2.5m//s^(2))t^(2)`. Find the average speed of the particle during the time '0' to '5' sec.

Text Solution

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The distance travelled by the particle from 0 to 5 sec is `S=2.5m//s^(2)xx5^(2)=62.5m`
Average speed during this time `V=S/t=62.5/5=12.5m//sec`.
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