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The near point of a Hypermetropic eye is...

The near point of a Hypermetropic eye is 1 m. What is the nature and powe of the lens required to correct this defect ? (The near point of the normal eye is 25 cm)

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The correct Answer is:
Convex lens +3.0 D
Given d=1m = 100 cm
For hypermetropic eye f`=(25d)/(d-25)=(25xx100)/(100-25)=(25xx100)/(75) = 33.33` cm
Power `P=(100)/("f(in cm)") =(100)/((100)/(3))=3D`
The lens is convex lens.
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