Home
Class 10
PHYSICS
Who proposed that conductors like metals...

Who proposed that conductors like metals a large number of the free electrons while the positive ions are fixed in their location ?

Text Solution

Verified by Experts

Drude and Lorentz.
Promotional Banner

Similar Questions

Explore conceptually related problems

A metallic resistor is connected across a battery. If the number of collisions of the free electrons with the lattice is some how decreased in the resistor (for example, by cooling it), the current will

Numerous forms of the periodic table have been devised from time to time. A modern version which is most convenient and widely used is the long or extended from of periodic table. The aufbau principle and the electronic configuration of atoms provide a theoretical foundation for the periodic classification. The horizontal rows are called periods. There are altogether seven periods. The first period consists of 2 elements. The subsequent periods consists of 8, 8,18, 18 and 32 elements respectively. The seventh period is incomplete and like the sixth period would have maximum of 32 elements. Elements having similar outer electronic configurations in their atoms are grouped in vertical columns. These are referred to as groups or families. According to the recommendations of IUPAC, the groups are numbered 1 to 18 replacing the older notation of groups 0, IA, IIA, ....VIIA, VIII, IB.....VIIB. Each successive period in the periodic table is associated with the filling up next higher principal energy level following aufbau sequence. The number of elements in each period is twice the number of atomic orbitals available in the energy level that is being filled. All the elements are classified into four blocks, i.e., s-block, p-block, d-block, and f-block depending on the type of atomic orbitals that are being filled with electrons. What is the position of the element in the periodic table satisfying the electronic configuration (n-1)d^1 ns^2 for n=4 ?

Atoms are complicated than hydrogen have more than one proton in their nucleus. Let z stands for the number of protons in a nucleus. Also imagine that an atom loses all but one of its electrons so that it changes into a positively charged ion with just one electron. Bohr.s formula for the energy levels of the hydrogen atom can easily be changed to apply to such ions The potential energy of electron in the ground state of He^(+) ion is

Atoms are complicated than hydrogen have more than one proton in their nucleus. Let z stands for the number of protons in a nucleus. Also imagine that an atom loses all but one of its electrons so that it changes into a positively charged ion with just one electron. Bohr.s formula for the energy levels of the hydrogen atom can easily be changed to apply to such ions What minimum amount of energy is required to bring an electron from ground state of Be^(3+) to infinity

Atoms more complicated than hydrogen have more than one proton in their nucleus. Let Z stands for the number of protons in a nucleus. Also imagine that an atom loses all but one of its electrons so that it changes into a positively charged ion with just one electron. Bohr.s formula for the energy levels of the hydrogen atom can easily be changed to apply to such ions. It becomes E_m = (-Z^2 e^4 m_e)/(8 epsi_0^2 h^2 n^2) , where m= mass of electron , e= change of electron, n = orbit number. The ionization potential of Het in ground state is

Conductors allow the passage of electric current through them. Metallic and electrolytic are the two types of conductors. Current carriers in metallic and electrolytic conductors are free electrons and free ions respectively. Specific conductance or conductivity of the electrolyte solution is given by the following relation: K= cx (l)/(A) where, c=1/R is the conductance and 1/A is the cell constant, Molar conductance (^^_m) and equivalence conductance (^^_e) of an electrolyte solution are calculated using the following similar relations: ^^_m = K xx (1000)/(M) ^^_(e) = K xx (1000)/(N) where, M and N are the molarity and normality of the solution respectively. Molar conductance of strong electrolyte depends on concentration : ^^_m = ^^_m^(0) - b sqrt(C) ^^_m^(0) = molar conductance at infinite dilution C = concentration of the solution b = constant The degrees of dissociation of weak electrolytes are calculated as alpha = (^^_m)/(^^_m^(0)) = (^^_e)/(^^_e^(0)) Which of the following decreases on dilution of electrolytic solution?

Conductors allow the passage of electric current through them. Metallic and electrolytic are the two types of conductors. Current carriers in metallic and electrolytic conductors are free electrons and free ions respectively. Specific conductance or conductivity of the electrolyte solution is given by the following relation: K= cx (l)/(A) where, c=1/R is the conductance and 1/A is the cell constant, Molar conductance (^^_m) and equivalence conductance (^^_e) of an electrolyte solution are calculated using the following similar relations: ^^_m = K xx (1000)/(M) ^^_(e) = K xx (1000)/(N) where, M and N are the molarity and normality of the solution respectively. Molar conductance of strong electrolyte depends on concentration : ^^_m = ^^_m^(0) - b sqrt(C) ^^_m^(0) = molar conductance at infinite dilution C = concentration of the solution b = constant The degrees of dissociation of weak electrolytes are calculated as alpha = (^^_m)/(^^_m^(0)) = (^^_e)/(^^_e^(0)) Which of the following equality holds good for the strong electrolytes?