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A = vec(i) + vec(j) . What is the angle...

A = `vec(i) + vec(j)` . What is the angle between the vector and x-axis ?

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Given that , `vec(A) = vec(i) + vec(j)`
`|vec(A)| = sqrt((1)^(2) + (1) ^(2)) = sqrt(2)`
If `theta` is the angle made by the vector with x-axis then ,
`cos theta = (A)/(|vec(A)|) rArr cos theta = (1) /(sqrt(2))rArr theta = 45^(@)`
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