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A Projectile is fired at an angle of 60...

A Projectile is fired at an angle of `60^(@)` to the horizontal with an initial velocity of 800 m / s :
Find the time of flight of the projectile before it hits the ground .

Text Solution

Verified by Experts

Angle of projection, `theta = 60^(@)` ,
Initial velocity, u = 800 ` m // s `
Time of flight , T `= (2 u sin theta)/(g)`
`= (2 xx 800)/(9.8) xx (sqrt(3))/(2) = (800 xx 1 * 732)/(9 * 8) = ( 141 * 4) sec`
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