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A Projectile is fired at an angle of 60...

A Projectile is fired at an angle of `60^(@)` to the horizontal with an initial velocity of 800 m / s :
Find the distance it travels before it hits the ground (range).

Text Solution

Verified by Experts

Angle of projection, `theta = 60^(@)` ,
Initial velocity, u = 800 ` m // s `
Range, R`= (u^(2) sin 2 theta)/(g)`
` = ( 800 xx 800 xx sin (2 xx 60^(@)))/(9*8)`
`rArr R = (800 xx 800)/(9*8)(sqrt(3))/(2)`
` = (800 xx 800)/(9 * 8) xx 0 . 8660 = 56 . 56 ` km .
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