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A Projectile is fired at an angle of 60...

A Projectile is fired at an angle of `60^(@)` to the horizontal with an initial velocity of 800 m / s :
Find the time of flight for the projectile toreach its maximum height .

Text Solution

Verified by Experts

Angle of projection, `theta = 60^(@)` ,
Initial velocity, u = 800 ` m // s `
Time of flight to reach maximum height ` = (T)/(2)`
`T_(1) = (2 u sin theta)/(2g) = (u sin theta)/(g) = (800 sin 60^(@))/(9.8)`
` = (800 xx 0 . 8660) / (9 . 80) = 70 . 7 ` sec
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