An aircraft executes a horizontal loop of radius 1 km with a steady speed of 900 km/h . Compare its centripetal acceleration with the acceleration due to gravity .

Explanation

Here, r = 1 km = 1000 m ,
v = 900 km `h^(-1) = 900 xx (1000 m ) xx (60 xx 60 s)^(-1)`
` = 250 ms^(-1)`
Centripetal acceleration, a ` = (v^(2))/(r) = ((250)^(2))/(1000)`
Now , `(a)/(g) = ((250)^(2))/(1000) xx (1)/(9.8) = 6 . 38`