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A bullet fired at an angle of 30^(@) wi...

A bullet fired at an angle of `30^(@)` with the horizontal hits the ground 3 . 0 km away. By adjusting its angle of projection, can one hope to hit a target 5 . 0 km away ? Assume the muzzle speed to be fixed, and neglect air resestance .

Text Solution

Verified by Experts

Horizontal range, R ` = (u^(2) sin 2 theta)/(g) ` or
`3 = (u^(2) sin 60^(@))/(g) = (u^(2))/(g)sqrt(3//2) or (u^(2))/(g) = 2 sqrt(3)`
Since the muzzle velocity is fixed , therefore, Max . Horizontal range,
`R_(max) = (u^(2))/(g) = 2 sqrt(3) = 3 . 464` m .
So , the bullet cannot hit the target .
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