A particle executes SHM such that, the maximum velocity during the oscillation is numerically equal to half the maximum acceleration. What is the time period?

Explanation

Given maximum velocity, `V_(max)=(1)/(2)` maximum acceleration `(a_(max))`
But `V_(max)=Aomega and a_(max)=omega^(2)A`
`therefore A omega=(1)/(2).A omega^(2) rArr omega=2`
Time period of the body ,`T=(2pi)/(omega)=(2pi)/(2)=pisec`