What would be the change in acceleration due to gravity at the surface, if the radius of Earth decreases by 2% keeping the mass of Earth constant?

Explanation

Acceleration due to gravity, `g=(GM)/(R^2)`
When mass is kept as constant and radius is decreased by 2% than `(triangleR)/(R )xx100=2`
From distribution of errors in multipications and divisions `(triangleg)/(g)xx100= -2(triangleR)/(R )xx100`
% Change in `g= -2xx2= -4%` -ve sign indicates that when R dereases 'g' increases.