How does the accleration due to gravity change for the same values of height and depth?

Explanation

Variation of 'g' with altitude: When we go to a height 'h' above the ground 'g' value decreases.
On surface of earth `(g)=(GM)/(R^2)`
At an altitude 'h' `g(h)=(GM)/((R+h)^2)` because R+h is the distance from centre of earth to the given point at 'h'.

So accleration due to gravity decreases with height above the ground.
Variation of 'g' with depth: When we go deep into the ground 'g' value decreases.
At a depth 'd' inside the ground mass of earth upto the point d from centre will exhibit force of attraction on the body. The remaining mass does not exhibit any influence. So effective radius is (R-d) only. Acceleration due to gravity 'g' at a depth 'd' is given by

So 'g' value decreases with depth below the ground.