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A satellite orbits the earth at a height...

A satellite orbits the earth at a height of 1000 km. Find orbital speed.

Text Solution

Verified by Experts

Radius of earth, R=6,400 km=`6.4xx10^(6) m`
Mass of earth, `M=6xx10^(24)`
Height of satellite, h=1000 km
`G=6.67xx10^(11) N-m^2`/`kg^2`.
Orbital velocity `V_(@)=sqrt((GM)/(R+h))`
`:.V_(@)=sqrt((6.67xx6xx10^(24))/(6400+1000))`
`=sqrt((6.67xx6xx10^(13))/(7.4xx10^(6)))=sqrt((40.02xx10^(7))/(7.4))`
`=7354m =7.354` km.
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