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A satellite orbits the earth at a height...

A satellite orbits the earth at a height equal to the radius of earth. Find its
orbital speed

Text Solution

Verified by Experts

Radius of earth, `R=6,400 km`
Mass of earth, `M=6xx10^(24)`
Height above earth, h=R.
`G=6.67xx10^(11) N-m^2`/`kg^2`.
Orbital velocity `V_(@)=sqrt((GM)/(R+h))=sqrt((GM)/(2R))`
`:.V_(@)=sqrt((6.67xx6xx10^(-11)xx6xx10^(24))/(2xx6.4xx10^(6))`
`=sqrt((40.02xx10^(13))/(12.8xx10^(6))=sqrt((40.02xx10^(7))/(12.8))`
=5592 m/s =`5.592` km/sec.
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