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A satellite orbits the earth at a height...

A satellite orbits the earth at a height equal to the radius of earth. Find its
Period of revolution.

Text Solution

Verified by Experts

Radius of earth, `R=6,400 km`
Mass of earth, `M=6xx10^(24)`
Height above earth, h=R.
`G=6.67xx10^(11) N-m^2`/`kg^2`
Time period, `T=(2pi(2R))/(V)`
`=(2xx3.142xx6.4xx10^6xx2)/(5592)=14,380 sec`
`=3.994h=4` hours.
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