A body weighs 63 N on the surface of Earth. What is the gravitational force on it due to the earth at a height equal to half the radius of the Earth?

Explanation

Weight of body =mg=63N
At height h, the value of g' is given by,
`g'=(gR^2)/((R+h)^2)=(gR^2)/((R+R/2)^2)=(4)/(9)g`
Gravitational force on body at a height h is
`F=mg'=mxx(4)/(9)g=(4)/(9)mg=(4)/(9)xx63=28N`