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1 mol benzene (P^(@)("benzene")=42 mm) ...

1 mol benzene `(P^(@)_("benzene")=42 mm)` and 2 mol toluence `(P^(@)_("toluene")=36 mm)` will have

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1 mole benzene (P_("benzene"^(@)=42"min")) will have

Consider the following partially labelled figure (graph is upto scale) for an ideal binary solution of benzene and toluence and answer the following questions. p_("total") = p_("benzene") +p_("toluene") and p_("total") = p_("benzene")^(@) or p_("toluene")^(@) , are simultaneously valid for:

The mole fraction of toluene in the vapour phase which is in equilibrium with a solution of benzene (P_(B)^(@)=120 "torr") and toluene (P_(T)^(@)=80 "torr") having 2.0 mol of each, is

The mole fraction of toluene in the vapour phase which is in equilibrium with a solution of benzene (P_(B)^(@)=120 "torr") and toluene (P_(T)^(@)=80 "torr") having 2.0 mol of each, is

The mole fraction of toluene in the vapour phase which is in equilibrium with a solution of benzene (P_(B)^(@)=120 "torr") and toluene (P_(T)^(@)=80 "torr") having 2.0 mol of each, is

The mole fraction of toluene in the vapour phase which is in equilibrium with a solution of benzene (P_(B)^(@)=120 "torr") and toluene (P_(T)^(@)=80 "torr") having 2.0 mol of each, is

Total vapour pressure of mixture of 1 mol volatile component A(P^(@)A="100 mm Hg") and 3 mol of volatile component B(P^(@)B="60 mm Hg") is 75 mm. For such case -

Total vapour pressure of mixture of 1 mol volatile component A(P^(@)A="100 mm Hg") and 3 mol of volatile component B(P^(@)B="60 mm Hg") is 75 mm. For such case -