If `(sinalpha)/(sinbeta)=(cosgamma)/(cosdelta), then (sin((alpha-beta)/2)*cos((alpha+beta)/2)*cosdelta)/(sin((delta-gamma)/2)*sin((delta+gamma)/2)*sinbeta)` is equal to

If (sin alpha)/(sin beta)=(cos gamma)/(cos delta), then (sin ((alpha-beta)/2) . cos ((alpha+beta)/2) . cos delta)/(sin ((delta-gamma)/2) . sin ((delta+gamma)/2) . sin beta)

If (sin alpha) / (sin beta) = (cos gamma) / (cos delta), then (sin ((alpha-beta) / (2)) * cos ((alpha + beta) / (2)) * cos delta) / (sin ((delta-gamma) / (2)) * sin ((delta + gamma) / (2)) * sin beta) is equal to

Show that sinalpha+sinbeta+singamma-sin(alpha+beta+gamma)=4sin ((alpha+beta)/2) sin((beta+gamma)/2)sin((gamma+alpha)/2)

(sinalpha+sinbeta-sin(alpha+beta))/(sinalpha+sinbeta+sin(alpha+beta))=tan(alpha/2)tan(beta/2)

If alpha,beta,gammain(0,pi/2) , then (sin(alpha+beta+gamma))/(sinalpha+sinbeta+singamma) is

Prove that: sinalpha+sinbeta+singamma-sin(alpha+beta+gamma)=4sin((alpha+beta)/2)sin((beta+gamma)/2)sin((gamma+alpha)/2)dot

If alpha,beta,gammain(0,pi/2) , then (sin(alpha+beta+gamma))/(sinalpha+sinbeta+singamma) is :

If cos (alpha + beta) sin (gamma + delta) = cos (alpha - beta) sin (gamma - delta) then: