sec x=2

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Solve : 1+2cosec x=-("sec"^(2)(x)/(2))/(2)

Solve : 1+2cosec x=-("sec"^(2)(x)/(2))/(2)

Solve : 1+2cosec x=-("sec"^(2)(x)/(2))/(2)

Find the most general solution of the following sec4x-sec2x=2

lim_(x rarr0)(sec4x-sec2x)/(sec3x-sec x)=

intx ((sec 2x-1)/(sec 2x+1))dx=

lim_(x rarr0)(sec x-1)/(x^(2)(sec x+1)^(2))=