Tripling the speed of the motor car multiplies the distance needed for stopping it by

A retarding force is applied to stop motor car. If- the speed of the motor car is doubled, how much more distance will it cover before stopping under the same retarding force?

7.If "50m" is the distance at which a car can be stopped when initially it was moving with speed "10ms^(-1)",then on making the speed of the car "50ms^(-1)",the distance at which the car can be stopped is (retardation is same in both cases)

A retarding force is applied to stop a motor car . If the speed of the motor car is doubled , how much more distance will it cover before stopping under the same retarding force ?

If x is the distance at which a car can be stopped when initially it was moving with speed u, then on making the speed of the car Nu, the distance at which the car can be stopped is

The distance between two places is 200 km. The time taken by moter car to travel from one place to another is more by 2 hrs than the time taken by a zeep car.If the speed of the motor car is 5 kms/hr less than the speed of the zeep car, then find the speed of the motor car.

The speed of a motor car becomes six times, then the kinetic energy becomes