`12 a^2 + b x^2 - 4ab - 3a x^2`

Applying formula of quadratic equation, solve the following equations. a^2b^2x^2 - (4b^4 - 3a^4)x - 12a^2b^2=0 .

, (a+b)^2 + (a-b)^2 = 2(a^2 + b^2) or (a+b)^2 - (a -b)^2= 4ab or ab = (frac(a+b)(2))^2 -(frac(a-b)(2))^2 to find the following. Let's find 8xy( x^2 + y^2 ) when (x+y) = 5 and (x-y) = 1

Factorise the using the identity a ^(2) + 2 ab + b ^(2) = (a + b) ^(2) 4x ^(4) + 12 x ^(3) + 9x ^(2)

Factorise the using the identity a ^(2) + 2 ab + b ^(2) = (a + b) ^(2) 4x ^(2) + 12 x + 9

Factorise the using the identity a ^(2) - 2 ab + b ^(2) = (a -b) ^(2). 9x ^(2) - 12 x + 4

Factorise the expression using the identity a ^(2) + 2 ab + b ^(2) = (a + b) ^(2) x ^(2) + 12 x + 36

Factorise : 4a^(2) - 4ab+ b^(2) - 4x^(2)

Factorise the using the identity a ^(2) + 2 ab + b ^(2) = (a + b) ^(2) (x ^(2))/( 4) + 2x +4

Factorise the using the identity a ^(2) - 2 ab + b ^(2) = (a -b) ^(2). (x ^(2))/(4) - 2x + 4

Factorise the using the identity a ^(2) + 2 ab + b ^(2) = (a + b) ^(2) 4x ^(2) + 4x +1