If `costheta_1 =2costheta_2,` then `tan((theta_1-theta_2)/2)tan((theta_1+theta_2)/2)` is equal to (a)`1/3` (b) `-1/3` (c)`1` (d) `-1`

If cos theta_(1)=2cos theta_(2), then tan((theta_(1)-theta_(2))/(2))tan((theta_(1)+theta_(2))/(2)) is equal to (a) (1)/(3)(b)-(1)/(3)(c)1(d)-1

If cos theta _(1) = 2 cos theta _(2), then tan (( theta _(1) + theta _(2))/(2)) tan (( theta _(1) - theta _(2))/(2)) is equal to

If : cos theta_(1) = 2 * cos theta_(2), ltbr gt "then" (tan""(theta_(1)-theta_(2))/(2))(tan""(theta_(1) + theta_(2))/(2))= A) (1)/(3) B) -(1)/(3) C)1 D)-1

If sintheta=costheta then 2tan^(2)theta+sin^(2)theta-1=___ .

If sintheta_1sintheta_2-costheta_1costheta_2+1=0, then the value of tan((theta_1)/2)cot((theta_2)/2) is equal to

If sintheta_1sintheta_2-costheta_1costheta_2+1=0, then the value of tan((theta_1)/2)cot((theta_2)/2) is equal to (a) -1 (b) 1 (c) 2 (d) -2

If sintheta_1sintheta_2-costheta_1costheta_2+1=0, then the value of tan((theta_1)/2)cot((theta_2)/2) is equal to (a) -1 (b) 1 (c) 2 (d) -2

If sintheta_1sintheta_2-costheta_1costheta_2+1=0, then the value of tan((theta_1)/2)cot((theta_2)/2) is equal to -1 (b) 1 (c) 2 (d) -2

if costheta_1+costheta_2+costheta_3=3 then sin^2theta_1+sin^4theta_2+sin^6theta_3=