" (i) "(x+1)(x+2)(x+3)(x+4)+1=0

Solve : (i)" "((x-1)\(x-2)(x-3))/((x+1)(x+2)(x+3))" "(ii) " "(x^(4)+x^(2)+1)/(x^(2)+4x-5)lt0

Solve : (i)" "((x-1)\(x-2)(x-3))/((x+1)(x+2)(x+3))" "(ii) " "(x^(4)+x^(2)+1)/(x^(2)+4x-5)lt0

(x+1)(x-3)(x+2)(x-4)+6=0

Solve: (x+1)(x+2)(x+3)(x+4)+1=0 .

(x - 2)(x + 4)-(x - 3)(x - 1) = 0

1/(x+1)-1/(x+2)-1/(x+3)+1/(x+4)=0 then x=

If f(x)=(1+x)(1+x^2)(1+x^3)(1+x^4) , then f'(0)=1

Without expanding, find the value of: (i) (x + 1)^4 - 4(x + 1)^3 (x - 1) + 6(x + 1)^2 (x - 1)^2 - 4(x + 1) (x - 1)^3 + (x -1)^4 (ii) (2x - 1)^4 + 4(2x - 1)^3 (3 - 2x) + 6(2x - 1)^2 (3 - 2x)^2 + 4(2x - 1) (3 - 2x)^3 + (3 - 2x)^4