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A simple pendulum simple harmonic motion...

A simple pendulum simple harmonic motion about `x = 0` with an amplitude a and time period `T` speed of the pendulum at `x = a//2` will be

A

`(piAsqrt3)/T`

B

`(piA)/T`

C

`(piAsqrt3)/(2T)`

D

`(3pi^(2)A)/(T)`

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • A simple pendulum simple harmonic motion about x = 0 with an amplitude a and time period T speed of the pendulum at s = a//2 will be

    A
    `(pi asqrt(3))/(2T)`
    B
    `(pi a)/(T) `
    C
    `(3pi^(2)a)/(T) `
    D
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    A
    `(pi a sqrt(3))/(2T)`
    B
    `(pi a)/(T)`
    C
    `(3pi^(2) a)/(T)`
    D
    `(pi a sqrt(3))/(T)`

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    A
    `(piAsqrt(3))/(T)`
    B
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