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A simple pendulum simple harmonic motion...

A simple pendulum simple harmonic motion about `x = 0` with an amplitude a and time period `T` speed of the pendulum at `x = a//2` will be

A

`(piAsqrt3)/T`

B

`(piA)/T`

C

`(piAsqrt3)/(2T)`

D

`(3pi^(2)A)/(T)`

Text Solution

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The correct Answer is:
A
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