A mass M is suspended by two springs of ...

A mass M is suspended by two springs of force constants `K_(1) and K_(2)` respectively as shown in the diagram. The total elongation (stretch) of the two springs is

` (mg)/(K_(1) + K_2)`

` (mg(K_(1)+K_(2)))/(K_(1)K_2)`

` (mgK_(1)K_(2))/(K_(1)+K_2)`

` (K_(1)+K_(2))/(K_(1)K_2mg)`

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