Home
Class 11
PHYSICS
Two simple pandulum whose lengths are 10...

Two simple pandulum whose lengths are `100cm` and `121cm` are suspended side by side. Then bobs are pulled together and then released. After how many minimum oscillations of the longer pendulum will two be in phase again. ?

A

11

B

10

C

21

D

20

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Similar Questions

Explore conceptually related problems

Two simple pandulum whose lengths are 100cm and 121cm are suspended side by side. Then bobs are pulled together and then released. After have minimum oscillation of the length pendulum will be two be in phase again. ?

Two simple pendulums of length 1m and 16m respectively are both given small displacements in the same direction at the same instant. After how many oscillations of the shorter pendulum will, the two pendulums vibrate in the same phase ?

Two pendulums of length 1.21 m and 1.0 m starts vibrationg. At some instant, the two are in the mean position in same phase. After how many vibrations of the longer pendulum, the two will be in phase ?

Two simple pendulums of length 0.4 m and 1.6 m respectively are given small linear displacements in one direction at the same ins"tan"t. After how many complete oscillations of the pendulum of the shorter length, they will again be in phase ?

Two simple pendulums of length 100m and 121m start swinging together. They will swing together again after

Two simple pendulum have lengths land ( 25l)/( 16) . At t=0 they are in same phase after how may oscillations of smaller pendulum will they be again in phase for first time ?

Two simple pendulums of length 5 m and 20 m are given small displacements in the same direction at the same time. The minimum number of oscillations, the shorter pendulum has completed, when the phase difference between them become zero again, is

Two simple pendulum of length l and 16l are released from the same phase together. They will be at the same time phase after a minimum time.

Two pendulums have time periods T and 5T//4 . They start SHM at the same time from the mean position After how many oscillations of the smaller pendulum they will be again in the same phase: