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Equations y(1) A sinomegat and y(2) = A...

Equations ` y_(1) A sinomegat and y_(2) = A/2 sin omegat + A/2 cos omega t `represent S.H.M. The ratio of the amplitudes of the two motions is

A

1

B

2

C

`0.5`

D

`sqrt2`

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The correct Answer is:
To solve the problem, we need to find the ratio of the amplitudes of the two simple harmonic motions (SHM) represented by the equations: 1. \( y_1 = A \sin(\omega t) \) 2. \( y_2 = \frac{A}{2} \sin(\omega t) + \frac{A}{2} \cos(\omega t) \) ### Step 1: Identify the amplitude of \( y_1 \) The amplitude of \( y_1 \) is straightforward since it is given directly in the equation: - Amplitude of \( y_1 = A \) ### Step 2: Simplify \( y_2 \) We need to express \( y_2 \) in a standard form to identify its amplitude. The equation is: \[ y_2 = \frac{A}{2} \sin(\omega t) + \frac{A}{2} \cos(\omega t) \] ### Step 3: Factor out the common term We can factor out \( \frac{A}{2} \): \[ y_2 = \frac{A}{2} \left( \sin(\omega t) + \cos(\omega t) \right) \] ### Step 4: Use the trigonometric identity To combine \( \sin(\omega t) + \cos(\omega t) \), we can use the identity: \[ \sin(\theta) + \cos(\theta) = \sqrt{2} \sin\left(\omega t + \frac{\pi}{4}\right) \] This means: \[ \sin(\omega t) + \cos(\omega t) = \sqrt{2} \sin\left(\omega t + \frac{\pi}{4}\right) \] ### Step 5: Substitute back into \( y_2 \) Now substituting this back into the equation for \( y_2 \): \[ y_2 = \frac{A}{2} \cdot \sqrt{2} \sin\left(\omega t + \frac{\pi}{4}\right) \] This simplifies to: \[ y_2 = \frac{A \sqrt{2}}{2} \sin\left(\omega t + \frac{\pi}{4}\right) \] ### Step 6: Identify the amplitude of \( y_2 \) From the equation, we can see that the amplitude of \( y_2 \) is: - Amplitude of \( y_2 = \frac{A \sqrt{2}}{2} \) ### Step 7: Calculate the ratio of the amplitudes Now we can find the ratio of the amplitudes of \( y_1 \) and \( y_2 \): \[ \text{Amplitude ratio} = \frac{\text{Amplitude of } y_1}{\text{Amplitude of } y_2} = \frac{A}{\frac{A \sqrt{2}}{2}} = \frac{A \cdot 2}{A \sqrt{2}} = \frac{2}{\sqrt{2}} = \sqrt{2} \] ### Final Answer The ratio of the amplitudes of the two motions is: \[ \sqrt{2} \] ---
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