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Two simple pendulum first of bob mass M(...

Two simple pendulum first of bob mass `M_(1)` and length `L_(1)` second of bob mass `M_(2)` and length `L_(2) M_(1) = M_(2)` and `L_(1)` = 2L_(2)`. if the vibrational energy of both is same which is correct?

A

Amlitude of B greater than A

B

Amplitude of B smaller than A

C

Amplitude will be same

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
B
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Two simple pendulum first of bob mass M_(1) and length L_(1) second of bob mass M_(2) and length L_(2) M_(1) = M_(2) and L_(1) = 2L_(2) . if these vibrational energy of both is same which is correct?

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