Home
Class 12
PHYSICS
An electron is moving in electron field ...

An electron is moving in electron field and magnetic field it will gain energy from

A

Electric field

B

Magnetic field

C

Both of these

D

None of these

Text Solution

AI Generated Solution

The correct Answer is:
To determine in which field an electron will gain energy while moving, we need to analyze the effects of both electric and magnetic fields on the electron. ### Step-by-Step Solution: 1. **Understanding the Electric Field:** - When an electron (which has a charge of -e) moves in an electric field (E), it experiences an electrostatic force given by: \[ F_E = Q \cdot E = -e \cdot E \] - The negative sign indicates that the force acts in the opposite direction to the electric field. 2. **Acceleration of the Electron:** - The acceleration (a) of the electron can be calculated using Newton's second law: \[ a = \frac{F_E}{m_e} = \frac{-e \cdot E}{m_e} \] - Since the force is in the same direction as the velocity of the electron (due to the negative charge), the electron will accelerate in the direction of the electric field. 3. **Change in Velocity:** - The velocity of the electron will increase as it accelerates: \[ V' = V_0 + a \cdot t \] - This increase in velocity indicates that the kinetic energy of the electron will also increase. 4. **Kinetic Energy in Electric Field:** - The kinetic energy (KE) of the electron is given by: \[ KE = \frac{1}{2} m_e V^2 \] - As the velocity increases, the kinetic energy will also increase. 5. **Understanding the Magnetic Field:** - When the electron moves in a magnetic field (B), it experiences a magnetic force given by: \[ F_B = Q \cdot (V \times B) = -e \cdot (V \times B) \] - The direction of this force is always perpendicular to both the velocity of the electron and the magnetic field. 6. **Effect of Magnetic Force:** - Since the magnetic force is always perpendicular to the velocity, it does not do work on the electron. Therefore, the speed (and thus the kinetic energy) of the electron remains constant: \[ KE = \frac{1}{2} m_e V^2 \quad \text{(constant)} \] 7. **Conclusion:** - In the electric field, the electron gains energy due to the work done by the electric force, leading to an increase in kinetic energy. - In the magnetic field, the electron does not gain energy because the magnetic force does not change its speed. ### Final Answer: The electron will gain energy from the **electric field**. ---
Promotional Banner

Topper's Solved these Questions

  • ELECTRON, PHOTON, PHOTOELECTRIC EFFECT AND X-RAYS

    ERRORLESS |Exercise Cathode Rays and Positive Rays|11 Videos
  • ELECTRON, PHOTON, PHOTOELECTRIC EFFECT AND X-RAYS

    ERRORLESS |Exercise Photon and Photoelectric Effect|4 Videos
  • ELECTRO MAGNETIC INDUCTION

    ERRORLESS |Exercise SET|20 Videos
  • ELECTRONICS

    ERRORLESS |Exercise Selv Evaluation Test|23 Videos

Similar Questions

Explore conceptually related problems

If an electron is moving with velocity v produces a magnetic field vecB , then

If an electron is going in the direction of magnetic field vecB with the velocity of vecv then the force on electron is

An electron is orbiting is a circular orbit of radius r under the influence of a constant magnetic field of strength B. Assuming that Bohr postulate regarding the quantisation of angular momentum holds good for this elerctron, find (a) the allowed values of te radius r of the orbit. (b) the kinetic energy of the electron in orbit (c ) the potential energy of insteraction between the magnetic moment of the orbital current due to the electron moving in its orbit and the magnetic field B. (d) the total energy of the allowed energy levels. (e) the total magnetic flux due to the magnetic field B passing through the nth orbit. (Assume that the charge on the electronis -e and the mass of the electron is m).

when an electron moves through a magnetic field , its speed will

Radius of an electron moving in a circle in constant magnetic field is two times that of an alpha particle in the same field. Then de-Broglie wavelength of electrons is x-times of the alpha -particle Here x is

An electron moving towards the east enters a magnetic field directed towards the north. The force on the electron will be directed