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The de - Broglie wavelength lambda assoc...

The de - Broglie wavelength `lambda` associated with an electron having kinetic energy `E` is given by the expression

A

`(h)/(sqrt(2mE))`

B

`(2h)/(mE)`

C

`2mhE`

D

`(2sqrt(2mE))/(h)`

Text Solution

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The correct Answer is:
A
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