Home
Class 12
PHYSICS
For the Bohr's first orbit of circumfere...

For the Bohr's first orbit of circumference ` 2pi r` , the de - Broglie wavelength of revolving electron will be

A

`2 pi r`

B

`pi r`

C

`(1)/(2pir)`

D

`(1)/(4 pi r)`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • ELECTRON, PHOTON, PHOTOELECTRIC EFFECT AND X-RAYS

    ERRORLESS |Exercise Cathode Rays and Positive Rays|11 Videos
  • ELECTRON, PHOTON, PHOTOELECTRIC EFFECT AND X-RAYS

    ERRORLESS |Exercise Photon and Photoelectric Effect|4 Videos
  • ELECTRO MAGNETIC INDUCTION

    ERRORLESS |Exercise SET|20 Videos
  • ELECTRONICS

    ERRORLESS |Exercise Selv Evaluation Test|23 Videos

Similar Questions

Explore conceptually related problems

If the radius of the first orbit of the hydrogen atom is 0.53 Å , then the de-Broglie wavelength of the electron in the ground state of hydrogen atom will be

If the radius of first Bohr's of hydrogen is x , then de - Broglie wavelength of electron in its 3rd orbit is

The de Broglie wavelength of an electron in the 3rd Bohr orbit is

If a_(0) be the radius of first Bohr's orbit of H-atom, the de-Broglie's wavelength of an electron revolving in the second Bohr's orbit will be:

The de-Broglie wavelength of an electron in the first Bohr orbit is

Assertion Second orbit circumference of hydrogen atom is two times the de-Broglie wavelength of electrons in that orbit Reason de-Broglie wavelength of electron in ground state is minimum.

If the radius of first Bohr orbit for hydrogen atom is x,then de-Broglie wavelength of electron in 4^( th ) orbit of H atom is nearly