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The de - Broglie wavelength lambda assoc...

The de - Broglie wavelength `lambda` associated with an electron having kinetic energy `E` is given by the expression

A

`lamda = (h)/(mE)`

B

`lamda =(sqrt(2mE))/(h)`

C

`lamda=(h)/(2mE)`

D

`lamda =(h)/(sqrt(2mE))`

Text Solution

Verified by Experts

The correct Answer is:
D
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