Home
Class 12
PHYSICS
If we express the energy of a photon in ...

If we express the energy of a photon in `KeV` and the wavelength in angstroms , then energy of a photon can be calculated from the relation

A

`E = 12.4 hv`

B

`E = 12.4 h//lamda`

C

`E = 12.4//lamda`

D

`E = hv`

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • ELECTRON, PHOTON, PHOTOELECTRIC EFFECT AND X-RAYS

    ERRORLESS |Exercise Cathode Rays and Positive Rays|11 Videos

  • ELECTRON, PHOTON, PHOTOELECTRIC EFFECT AND X-RAYS

    ERRORLESS |Exercise Photon and Photoelectric Effect|4 Videos

  • ELECTRO MAGNETIC INDUCTION

    ERRORLESS |Exercise SET|20 Videos

  • ELECTRONICS

    ERRORLESS |Exercise Selv Evaluation Test|23 Videos

Similar Questions

Explore conceptually related problems

Energy of a photon is given by the relation

The energy of a photon in eV of wavelength lambda nm will be

The energy of a photon of wavelength lamda is given by

The energy of a photon (in ev) of wavelength 5000 Å will be

The energy of a photon of wavelength 390 nm is nearly

The energy of a photon of wavelength lambda is given by

The energy of a photon of radiation having wavelength 300 nm is,

What is the energy of photons with a wavelength of 434 nm?

What is the energy of photon whose wavelength is 6840 Å ?

Energy of an emitted photon with wavelength 620 nm is :