Home
Class 12
PHYSICS
When a metal surface is illuminated by l...

When a metal surface is illuminated by light wavelengths `400 nm` and `250 nm` , the maximum velocities of the photoelectrons ejected are `upsilon` and `2 v` respectively . The work function of the metal is
`( h = "Planck's constant" , c = "velocity of light in air" )`

A

`2hc xx 10^(6) J`

B

`1.5 hc xx 10^(6) J`

C

`hc xx 10^(6) J`

D

`0.5 hc xx 10^(6) J`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • ELECTRON, PHOTON, PHOTOELECTRIC EFFECT AND X-RAYS

    ERRORLESS |Exercise Cathode Rays and Positive Rays|11 Videos
  • ELECTRON, PHOTON, PHOTOELECTRIC EFFECT AND X-RAYS

    ERRORLESS |Exercise Photon and Photoelectric Effect|4 Videos
  • ELECTRO MAGNETIC INDUCTION

    ERRORLESS |Exercise SET|20 Videos
  • ELECTRONICS

    ERRORLESS |Exercise Selv Evaluation Test|23 Videos

Similar Questions

Explore conceptually related problems

A metallic surface is illuminated alternatively with lights of wavelengths 3000A and 6000A . It is obseved that the maximum speeds of the photoelectrons under these illumination are in the ratio 3:1 Q. The work function of the metal is

A photonsensitive metallic surface is illuminated alternately with light of wavelength 3100 Å and 6200 Å . It is observed that maximum speeds of the photoelectrons in two cases are in ratio 2 : 1 . The work function of the metal is (hc = 12400 e VÅ)

The surface of a metal is illuminated with light of wavelength 400 nm. The kinetic energy of the ejected photoelectrons was found to be 1.68 eV. What is the work function of the metal ? [ hC=1240 eV*nm ]

A light of wavelength 600 nm is incident on a metal surface. When light of wavelength 400 nm is incident, the maximum kinetic energy of the emitted photoelectrons is doubled. The work function of the metals is

Light of wavelength 4000 Å is incident on a metal surface. The maximum kinetic energy of emitted photoelectron is 2 eV. What is the work function of the metal surface ?

A metal surface is illuminated by light of two different wavelengths 248 nm and 310 nm. The maximum speeds of the photoelectrons corresponding to these wavelengths are mu_1 and mu_2 respectively. If the ratio u_1: u_2 = 2:1 and hc= 1240 eV nm, the work function of the metal is neraly. (a)3.7 eV (b) 3.2 eV (c ) 2.8eV (d) 2.5eV.

On a metal with work function 2.0 eV light of wavelength 400 nm falls, maximum velocity of ejected photoelectron are 6.22xx10^(x)m//s. . Hence x is :

A metallic surface is illuminated alternatively with light of wavelenghts 3000 Å and 6000 Å . It is observed that the maximum speeds of the photoelectrons under these illuminations are in the ratio 3 : 1 . Calculate the work function of the metal and the maximum speed of the photoelectrons in two cases.