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Consider an aqueous solution 0.1 M each ...

Consider an aqueous solution 0.1 M each in HOCN, HCOOH, `(COOH)_2` and `H_3PO_4` for HOCN, we can write `K_a(HOCN)=([H^+][OCN^-])/([HOCN]),[H^+]` in the expression refers to:

A

`H^+` ions released by HOCN

B

Sum of `H^+` ion released by all monoprotic acids

C

Sum of `H^+` ions released by only the first dissociation of all the acids

D

Overall `H^+` ion concentration in the solution

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d
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