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pH of 0.01 M HS^(-) will be:...

`pH` of `0.01 M HS^(-)` will be:

A

`pH=7+(pK_a)/2+(log C)/2`

B

`pH=7-(pK_a)/2+(log C)/2`

C

`pH=7+(pK_1+pK_2)/2`

D

`pH=7+((pK_a+pK_b)/2)`

Text Solution

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The correct Answer is:
a
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