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The solubility product Mg(OH)(2) in wate...

The solubility product `Mg(OH)_(2)` in water at `25^(@)C` is `2.56xx10^(-13) ("mol"//"lt")^(3)` while that of `Al(OH)_(3)` is `4.32xx10^(-34) ("mol"//"lt")^(4)`. If `s_(1) " and " s_(2)` are the solubilities of `Mg(OH)_(2) " and " Al(OH)_(3)` in water in mol/lt at `25^(@)C`, what is the ratio, `s_(1)//s_(2)` ?

A

`2xx10^(5)`

B

`2xx10^(4)`

C

`3xx10^(6)`

D

`3xx10^(3)`

Text Solution

Verified by Experts

The correct Answer is:
b
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