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The solubility product of AgCl is 10^(-1...

The solubility product of AgCl is `10^(-10)`. The minimum volume (in L) of water required to dissolve 1.722 mg of AgCl (molecular weight of AgCl=143.5) :

A

10 lt

B

2.2 lt

C

1.2 lt

D

20 lt

Text Solution

Verified by Experts

The correct Answer is:
c
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