What will be the result when 15.0 mL of 0.040M lead(II) nitrate is mixed with 15.0 mL of 0.040M sodium chloride? `PbCl_(2)(s)rarrPb^(2+)(aq)+2Cl^(-)(aq)` [`K_(p)=1.7xx10^(-5)`]

Options

A. A clear solution with no precipitate will result.
B. Solid `PbCl_(2)` will precipitate and excess `Pb^(2+)` ions will remain in solution.
C. Solid `PbCl_(2)` will precipitate and excess `Cl^(-)` ions will remain in solution
D. Solid `PbCl_(2)` will precipitate and no excess ions will remain in solution.

Answer

a