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Stroniyum fluoride (SrF(2.)) is a sparin...

Stroniyum fluoride `(SrF_(2.))` is a sparingly soluble slat. Let`s_(1)` be its solubility (in mol/lt.) in pure water at `25^@C`, assuming no hydrolysis of `F^(-)` ions. Also let `s_(2)` be its solubility (in hydrolysis of `F^(-)`ion and no complex formation. However,it is known that `s_(1):s_(2)=10^(6):256`.
The solubility of `SrF_(2)` (in mol/L) in a buffer solution of pH=5 at `25^(@)`C is :

A

`1.6xx10^(-3)`

B

`3.2xx10^(-3)`

C

`4.8xx10^(-3)`

D

`6.4xx10^(-3)`

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The correct Answer is:
b
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Stroniyum fluoride (SrF_(2.)) is a sparingly soluble slat. Let s_(1) be its solubility (in mol/lt.) in pure water at 25^@C , assuming no hydrolysis of F^(-) ions. Also let s_(2) be its solubility (in hydrolysis of F^(-) ion and no complex formation. However,it is known that s_(1):s_(2)=10^(6):256 . The K_(sp) value of SrF_(2) at 25^(@) C is :

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GRB PUBLICATION-IONIC EQUILIBRIUM-All Questions
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  2. Stroniyum fluoride (SrF(2.)) is a sparingly soluble slat. Lets(1) be i...

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  3. Stroniyum fluoride (SrF(2.)) is a sparingly soluble slat. Lets(1) be i...

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  18. The Ph of basic buffer mixtures is given by : Ph=Pk(a)+log (["Base"])...

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