Acetic acid tends to form dimer due to formation of intermolcular hydrogen bonding.
`2CH_(2)COOHhArr(CH_(3)COOH)_(2)`
The equilibrium constant for this reaction is `1.5xx10^(2)M^(-1)`in benzene solution and `3.6xx10^(-2)` in water. In benzene, monomer does not dissociate but it water, monomer dissociation simultaneously with acid dissociation constant `2.0xx10^(-5)`M. Dimer does not dissociate in benzene as well as water.
The molar ratio of dimer to monmer for 0.1M acetic acid in water (neglecting the dissciation of acetic acid in water ) is equal to :

Options

A. `250:1`
B. `1:250`
C. `9:2500`
D. `2500:9`

Answer

c