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100ml of 0.1M H(3)PO(4) is titrated with...

100ml of 0.1M `H_(3)PO_(4)` is titrated with 0.05 M NaOH solution till 2nd equivalent point. Then, resultant solution was mixed with 10 ml of 0.5 MHCI solution
`K_(1)=10^(-3)M`
`K_(2)=10^(-8)M`
`K_(3)=10^(-13)M`
pH at 2nd equivalent point will be :

A

`5.5`

B

`10.5`

C

`8`

D

`7`

Text Solution

Verified by Experts

The correct Answer is:
b
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