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Selective precipitation of ions in a mix...

Selective precipitation of ions in a mixture in the form of salts can be adding common ions gradually. Let us condsider selective precipitation of `CI^(-)` and `CrO_(4)^(2-)`ions in the form of AgCl and `Ag_(2)Cro_(4)` form a mixture having having 0.01M `CI^(-)` and 0.01M `CrO_(4)^(2-)`. For this, salt having `Ag^(+)` [like `AgNO_(3)(s)`] is added gradually. Given : `K_(sp) [AgCI]=10^(-10)` and `K_(sp)[Ag_(2)CrO_(4)]=4xx10^(-14)`
Minimum concentration of `Ag^(+)` ion at which precipitation of at least one ion starts.

A

`10^(8)M`

B

`1.41xx10^(-6)M`

C

`10^(-10)M`

D

`2xx10^(-6)M`

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The correct Answer is:
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Selective precipitation of ions in a mixture in the form of salts can be adding common ions gradually. Let us condsider selective precipitation of CI^(-) and CrO_(4)^(2-) ions in the form of AgCl and Ag_(2)Cro_(4) form a mixture having having 0.01M CI^(-) and 0.01M CrO_(4)^(2-) . For this, salt having Ag^(+) [like AgNO_(3)(s) ] is added gradually. Given : K_(sp) [AgCI]=10^(-10) and K_(sp)[Ag_(2)CrO_(4)]=4xx10^(-14)] The percentage of one ion precipitated when another ion starts precipitation is : (Given: (1)/(sqrt2)=0.7 )

Solid AgNO_(3) is gradually added to a solution which is 0.01M n Cl^(-) and 0.01 M in CO_(3)^(2-) K_(sp) AgCl=1.8xx10^(-10) and K_(sp)Ag_(2)CO_(3)=4xx10^(-12) The minimum concentration of Ag^(+) required to start the precipation of Ag_(2)CO_(3) is

Solid AgNO_(3) is gradually added to a solution which is 0.01M n Cl^(-) and 0.01 M in CO_(3)^(2-) K_(sp) AgCl=1.8x10^(-10) and K_(sp)Ag_(2)CO_(3)=4xx10^(-12) The cocentration of Cl^(-) when Ag_(2)CO_(3) starts precipating is

The solubility product of Ag CrO_(4) is 32xx10^(-12). What is the concentration of CrO_(4)^(2-) ions in that solution ?

A solution is 0.1 M in Cl^(-) and 0.001 M in CrO_(4)^(2-) . Solid AgNO_(3) is gradually added to it. Assuming that the addition does not change in volume and K_(SP) (AgCl) = 1.7 xx 10^(-10) M^(2) and K_(SP)(Ag_(2)CrO_(4)) = 1.9 xx 10^(-12) M^(3) . Select correct statement from the following:

To an aqueous solution of Ag_(2)CrO_(4) above its own precipitate , CrO_(4)^(2-) ions are added in the form of solution. This results in

A solution contains 0.1 M is Cl^(-) and 10^(-4) M CrO_(4)^(2-) . If solid AgNO_(3) is gradually added to this solution, what will be the concentration of Cl^(-) when Ag_(2)CrO_(4) begins to precipitate? (Ksp (AgCl) = 10^(-10) M^(2) , K_(sp) (Ag_(2)CrO_(4)) = 10^(-12)M^(3))

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