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The equilibrium equation and K(a) values...

The equilibrium equation and `K_(a)` values for the three acids are given at `25^(@)C`:
`HA(aq)+H_(2)OhArrH_(3)O^(+)(aq)+A^(-)(aq),K_(a)=2xx10^(-5)`
`HB(aq)+H_(2)OhArrH_(3)O^(+)(aq)+B^(-)(aq),K_(a)=4xx10^(-6)`
`HC(aq)+H_(2)OhArrH_(3)O^(+)(aq)+C^(-)(aq),K_(a)=1xx10^(-4)`
The pH of 0.1M aqueous NaC solution is : (NaC is sodium salt of acid HC)

A

`2.5`

B

`11.5`

C

`9.5`

D

`8.5`

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The correct Answer is:
d
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The equilibrium equation and K_(a) values for the three acids are given at 25^(@)C : HA(aq)+H_(2)OhArrH_(3)O^(+)(aq)+A^(-)(aq),K_(a)=2xx10^(-5) HB(aq)+H_(2)OhArrH_(3)O^(+)(aq)+B^(-)(aq),K_(a)=4xx10^(-6) HC(aq)+H_(2)OhArrH_(3)O^(+)(aq)+C^(-)(aq),K_(a)=1xx10^(-4) The pH of 0.2M aqueous HA solution is :

The equilibrium equation and K_(a) values for the three acids are given at 25^(@)C : HA(aq)+H_(2)OhArrH_(3)O^(+)(aq)+A^(-)(aq),K_(a)=2xx10^(-5) HB(aq)+H_(2)OhArrH_(3)O^(+)(aq)+B^(-)(aq),K_(a)=4xx10^(-6) HC(aq)+H_(2)OhArrH_(3)O^(+)(aq)+C^(-)(aq),K_(a)=1xx10^(-4) Which conjugate pair would be best for preparing a buffer witha pH =54? (log 2=0.3).

2H_(2)OhArrH_(3)O^(+)+OH^(-) K_(w)=1xx10^(-14) at 25^(@)C . Hence, K_(a) is:

What are conjugate acids and bases ? Select the conjugate acid-base pair from the following reactions: NH_3(aq) +H_2O(l)hArr NH_4^(+)(aq) +OH^(-) (aq) HCN(aq) + H_2O(l) hArr H_3O^(+)(aq) +CN^(-) (aq)

The equilibrium constant for the reaction given is 3.6xx10^(-7)OCl^(-)(aq)+H_2O(l)hArrHOCl(aq)+OH^(-)(aq). What is Ka for HOCl ?

For ortho phosphoric acid, H_3PO_4(aq)+H_2O(aq) to H_3O^(+)(aq)+H_2PO_4^(-)(aq),K_(a_1) H_2PO_4^-(aq)+H_2O(aq) to H_3O^(+)(aq)+H_2PO_4^(-)(aq),K_(a_2) HPO_4^(2-)(aq)+H_2O(aq) to H_3O^(+)(aq)+PO_3^(4)(aq),K_(a_3) The correct order of K_a values is :

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