`1.0L` of solution which was in equilibrium with solid mixture of `AgCI` and `Ag_(2)CrO_(4)` was found to contain `1 xx 10^(-4)` moles of `Ag^(+)` ions, `1.0 xx 10^(-6)`moles of `CI^(-)` ions and `8.0 xx 10^(-4)` moles of `CrO_(4)^(2-)` ions. At constant volume, `Ag^(+)` ions are added slowly to the above mixture till `8.0 xx 10^(-7)` moles of `AgCI` got precipitated. How many moles of `Ag_(2)CrO_(4)` were also precipitated ? Given your answer after multiplying with `10^(6)`.

Answer

`0768`