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Calculate pH when 100ml of 0.1M NaOh is ...

Calculate pH when 100ml of `0.1M NaOh` is reacted with `100ml` of `0.2M CH_(3)COOH. (K_(a) = 10^(-5))`

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What is the total volume of solution ( in ml), when 1M NaOH is required to be added in 100ml of 1M CH_(3) COOH ( K_(a) = 10^(-5)) solution so that its pH becomes 6

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Calculate the pH of each of the following solution (i) 100 ml of 0.1 M CH_(3)COOH mixed with 100 ml of 0.1 M NaOH. (ii) 100 ml of 0.1 M CH_(3)COOH mixed with 50 ml of 0.1 m NaOH (iii) 50 ml of 0.1 M CH_(3)COOH mixed with 100 ml of 0.1 M NaOH. K_(a)(CH_(3)COOH)=1.8xx10^(-5)

Calculate the pH at the equivalence point when a solution of 0.1 M CH_3COOH is titrated with a solution of 0.1 M NaOH. K_a(CH_3COOH)= 1.8 xx 10^(-5)

100ml of 0.75 N NH_(4)OH is mixed with 100ml of 0.25 N HCl. The K_(b) of NH_(4) OH = 2 xx 10^(-5) . Hence pH of solution is .

200ml of 1 M CH_(3)COOH(K_(a)=10^(-6)) is mixed with 200ml of 0.1M HCOOH(K_(a)=10^(-5)) . The pH of the resulting mixture is

pH when 100 mL of 0.1 M H_(3)PO_(4) is titrated with 150 mL 0.1 m NaOH solution will be :

Calculate pH of the mixture ( 50 mL of 0.05 M NH_(4)OH + 50 mL of 0.05 M CH_(3)COOH ) Given that K_(a) = 1.8 xx 10^(-5) , and K_(b) = 1.8 xx10^(-5)

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