`3(250)^(1/3)+7(16)^(1/3)-4(54)^(1/3)`

(16)^(^^)(1/3)+(54)^(^^)(1/3)+(192)^(^^)(1/3)-(375)^(^^)(1/3)

{(1/3)^2}^4 is equal to (a) (1/3)^6 (b) (1/3)^8 (c) (1/3)^(24) (d) (1/3)^(16)

{(1/3)^2}^4 is equal to (1/3)^6 (b) (1/3)^8 (c) (1/3)^(24) (d) (1/3)^(16)

Simplify : 5root(3)(250)+7root(3)(16)-14root(3)(54)

A rationalizing factor of (16)^((1)/(3))-(4)^((1)/(3))+1 is

{(81)^(-3/4)xx((16)^(1/4))/(6^(-2))xx(1/27)^(-4/3)}^(1/3)=

Solve (a) 2/3 + 1/7 (b) 3/10 + 7/15 (c) 4/9 + 2/7 (d) 5/7 + 1/3 (e) 2/5 + 1/6 (f) 4/5 + 2/3 (g) (3/4) (1/3) (h) (5/6) (1/3) (1) 2/3 + 3/4 + 1/2 (1) 1/2 + 1/3 = 1/6 (k) (1) 1/3 + (3) 2/3 (1) (4) 2/3 +(3) 1/4 (m) ((16)/5))(7/5)

Solve (a) 2/3 + 1/7 (b) 3/10 + 7/15 (c) 4/9 + 2/7 (d) 5/7 + 1/3 (e) 2/5 + 1/6 (f) 4/5 + 2/3 (g) (3/4) (1/3) (h) (5/6) (1/3) (1) 2/3 + 3/4 + 1/2 (1) 1/2 + 1/3 = 1/6 (k) (1) 1/3 + (3) 2/3 (1) (4) 2/3 +(3) 1/4 (m) ((16)/5))(7/5)

(3)/(4)+2(1)/(4) of (2)/(3)-((1)/(2)-(1)/(3))/((1)/(2)+(1)/(3))xx3(1)/(3)+(5)/(6)=?(7)/(18)(b)(49)/(54)(c)(2)/(3)(d)(1)/(6)