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When a solution of palmitic acid (Mol. M...

When a solution of palmitic acid (Mol. Mass = 256) in benzene containing 5.12 gm of acid/lit. is dropped on water surface, the benzene evaporates and the acid forms a monolayer film. The area covered by one molecule of palmitic acid is `1.54 nm^(2)`. Assuming each molecule of palmitic acid to be a sphere, answer the question that follow. `[N_(A) = 6xx10^(23)]`
What volume of solution must be dropped on the water surface in order to cover a surface area of `1848 cm^(2)`?

A

`10^(-2) lit`.

B

`10^(-5)ml`

C

`10^(-2) ml`

D

`10^(-4) lit`.

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The correct Answer is:
C
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When a solution of palmitic acid (Mol. Mass = 256) in benzene containing 5.12 gm of acid/lit. is dropped on water surface, the benzene evaporates and the acid forms a monolayer film. The area covered by one molecule of palmitic acid is 1.54 nm^(2) . Assuming each molecule of palmitic acid to be a sphere, answer the question that follow. [N_(A) = 6xx10^(23)] What is the approx density of each molecule of palmitic acid?

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