The edge length of unit cell of a metal `(Mw = 24)` having cubic structure is `4.53 Å`. If the density of metal is `1.74 g cm^(-3)`, the radius of metal is `(N_(A) = 6 xx 10^(23))`

A metal has an fcc latticed.The edge length of the unit cell is 404 pm .The density of the metal is 2.72 g//cm^(-3) .The molar mass of the metal is (N_(A) Avogadro's constant = 6.2 xx 10^(23) mol^(-1))

A metal has an fcc latticed.The edge length of the unit cell is 404 pm .The density of the metal is 2.72 g//cm^(-3) .The molar mass of the metal is (N_(A) Avogadro's constant = 6.2 xx 10^(23) mol^(-1))

The edge length of unit cell of a metal having molecular weight 75 g/mol is 5 Å which crystallises in cubic lattice. If the density is 2g//cm^(3) then, find the radius of metal atom. (N_(A)=6.022 xx 10^(23))

The edge length of unit cell of a metal having molecular weight 75 g mol^(-1) is 5 Å which crystallizes in cubic lattice. If the density is 2 g cc^(-3) , then find the radius of metal atom (N_(A) = 6 xx 10^(23)) . Give the answer in pm.

A metal has a fcc lattice.The edge length of the unit cell is 404 pm ,the density of the metal is 2.72g cm^(-3) . The molar mass of the metal is (N_(A) , Avorgadro's constant =6.02xx10^(23)mol^(-1))

A metal has a fcc lattice.The edge length of the unit cell is 404 pm ,the density of the metal is 2.72g cm^(-3) . The molar mass of the metal is (N_(A) , Avorgadro's constant =6.02xx10^(23)mol^(-1))